Chemistry
Bonding, shape and intermolecular forces
- 1.
Explain why molten sodium chloride conducts electricity but solid sodium chloride does not.
[3 marks] · no calculatorAnswer explanation
Draft walkthroughs are based on marking guidance, not independently verified derivations.
- Conduction requires mobile charged particles. Melting frees the ions from fixed lattice positions; it does not turn them into free electrons.
Marking points
- Charge carriers are ions.
- Solid ions are fixed in a lattice.
- Molten ions move and carry charge.
Examiner tip: Name the mobile particles; 'particles move' alone does not identify a current carrier.
- 2.
Predict the shape of CO2 and explain why its polar bonds do not produce a permanent molecular dipole.
[3 marks] · no calculatorAnswer explanation
Draft walkthroughs are based on marking guidance, not independently verified derivations.
- Treat each double bond as one region of electron density. The symmetric linear geometry makes the two dipole vectors sum to zero.
Marking points
- Two bonding regions around carbon give a linear shape.
- Each C=O bond is polar towards oxygen.
- Equal opposite bond dipoles cancel.
Examiner tip: Nonpolar molecules can still contain polar bonds.
- 3.
Compare the H-N-H and H-O-H bond angles in ammonia and water using electron-pair repulsion.
[3 marks] · no calculatorAnswer explanation
Draft walkthroughs are based on marking guidance, not independently verified derivations.
- The reference arrangement is tetrahedral. Lone pairs occupy more space than bonding pairs; replacing another bond pair with a lone pair further compresses the angle between the remaining bonds.
Marking points
- Both central atoms have four electron-pair regions.
- Water has two lone pairs; ammonia has one.
- Greater lone-pair repulsion compresses water's bond angle more.
Examiner tip: Distinguish electron-pair geometry from molecular shape.
- 4.
Ethanol has a higher boiling point than dimethyl ether although they share a molecular formula. Explain this difference.
[3 marks] · no calculatorAnswer explanation
Draft walkthroughs are based on marking guidance, not independently verified derivations.
- The formula alone cannot describe connectivity. Ether's oxygen can accept a hydrogen bond from water, but ether molecules cannot supply the required O-H hydrogen to each other.
Marking points
- Ethanol contains an O-H group.
- Ethanol molecules form hydrogen bonds with each other; pure ether lacks an O-H donor.
- More energy is needed to overcome ethanol's intermolecular attractions.
Examiner tip: Boiling separates molecules; it does not break their covalent bonds.
- 5.
A material is hard, has a very high melting point and does not conduct when solid. Evaluate whether these observations prove it is diamond.
[4 marks] · no calculatorAnswer explanation
Draft walkthroughs are based on marking guidance, not independently verified derivations.
- Use each observation to constrain a structural model. Hardness and thermal stability support an extended network, but physical properties are not a unique fingerprint of chemical composition.
Marking points
- The observations are consistent with a giant covalent network.
- Many strong covalent bonds require much energy to disrupt.
- Diamond lacks mobile electrons or ions.
- They do not prove diamond: other materials such as silica can fit; composition/structural evidence is needed.
Examiner tip: Separate 'consistent with' from 'uniquely proves'.
- 6.
Explain why graphite conducts along its layers and is soft, whereas diamond is insulating and hard, despite both being carbon.
[4 marks] · no calculatorAnswer explanation
Draft walkthroughs are based on marking guidance, not independently verified derivations.
- Relate two different properties to two different structural features: electron mobility explains conduction, while connectivity and interlayer attraction explain mechanical behaviour.
Marking points
- Graphite carbon bonds to three neighbours, leaving delocalised electrons.
- Delocalised electrons carry charge within layers.
- Weak attractions between layers allow sliding.
- Diamond has a rigid three-dimensional covalent network with electrons localised in bonds.
Examiner tip: Do not describe graphite's bonds within a layer as weak.
Marking points are indicative, not an official mark scheme. Accept equivalent valid methods and supported interpretations that address the task; award each mark once without requiring the model wording.